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<blockquote data-quote="ziphnor" data-source="post: 70288" data-attributes="member: 14215">Its chosen at the beginning and is fixed. I did consider to make it random per line, but thought id try it without first. Actually i think it might be better to just use equi-distant points instead,I tried that first when i tried to just process brightness and it slowed things down alot. But that may have been because i was calling image.GetBrightness() while i am now relying on image.B/R/G.Well, i suppose that for example a dark red-ish and dark blue-ish pixel might have the same intensity, which would land them in the same low intensity histogram 'bucket', while the above method would count such color difference along way towards being image content. My intuition was just to get a measure of the overall variance of the line(color included), as even very dark images will vary quite a bit, while the bars will have a more uniform dark. My previous attempts tried to spot jumps in the average brightness of lines, and it failed miserably.</blockquote>

[QUOTE="ziphnor, post: 70288, member: 14215"] Its chosen at the beginning and is fixed. I did consider to make it random per line, but thought id try it without first. Actually i think it might be better to just use equi-distant points instead, I tried that first when i tried to just process brightness and it slowed things down alot. But that may have been because i was calling image.GetBrightness() while i am now relying on image.B/R/G. Well, i suppose that for example a dark red-ish and dark blue-ish pixel might have the same intensity, which would land them in the same low intensity histogram 'bucket', while the above method would count such color difference along way towards being image content. My intuition was just to get a measure of the overall variance of the line(color included), as even very dark images will vary quite a bit, while the bars will have a more uniform dark. My previous attempts tried to spot jumps in the average brightness of lines, and it failed miserably. [/QUOTE]

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