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<blockquote data-quote="Dj_Moren" data-source="post: 585340" data-attributes="member: 99375">Hi, first of all, sorry for my bad english, i'm from Spain.The question i have is this: i'm adjusting a scrapper to my needs, because the actual scrapper sometimes receives the name bad. I've been searching for info here, in the FAQ and in <a href="http://moving-pictures.tv/wiki/Scraper_Engine" target="_blank">Scraper Engine - Moving Pictures</a> and i haven't seen the answer for my doubt. In the <a href="http://moving-pictures.tv/wiki/Scraper_Engine" target="_blank">Scraper Engine - Moving Pictures</a> site i have found the variables that are passed to the scrapper. The variable named ${search} is a collection of information, but this information is parsed previously. I mean that i want to be able to read in the parser the file's name exactly, and not start working with ${search.title} that comes previously parsed.Is this possible? Exists any variable name that corresponds with the file name as is?Thanks for your help.</blockquote>

[QUOTE="Dj_Moren, post: 585340, member: 99375"] Hi, first of all, sorry for my bad english, i'm from Spain. The question i have is this: i'm adjusting a scrapper to my needs, because the actual scrapper sometimes receives the name bad. I've been searching for info here, in the FAQ and in [url=http://moving-pictures.tv/wiki/Scraper_Engine]Scraper Engine - Moving Pictures[/url] and i haven't seen the answer for my doubt. In the [url=http://moving-pictures.tv/wiki/Scraper_Engine]Scraper Engine - Moving Pictures[/url] site i have found the variables that are passed to the scrapper. The variable named ${search} is a collection of information, but this information is parsed previously. I mean that i want to be able to read in the parser the file's name exactly, and not start working with ${search.title} that comes previously parsed. Is this possible? Exists any variable name that corresponds with the file name as is? Thanks for your help. [/QUOTE]

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