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<blockquote data-quote="RoChess" data-source="post: 1092311" data-attributes="member: 18896">RegExp is actually pretty easy once you break it up into small groups. Expresso is an awesome builder/tester of expressions, and it also auto-breaks the long expressions up.&nbsp;(...) capture group(?&lt;name&gt;....) named capture group(?:....) capture group, but excluded from results&nbsp;As to the one for you:&nbsp;|\s*\[[A-Z\s,]+\]| = like an 'or', so A|B means look for A or B, so it can be added to the existing one\s = space, \s* means look for 0+ spaces, if you want to force 1+, then it would be \s+\[ = the actual '[' char, because [ is used in Regular Expressions you have to 'escape' it.[...]+ = match all the characters within at least 1+, including ranges A-Z = A to Z, \s = space, &quot;,&quot; = comma\] the actual ']' char, because ] is used in Regular Expressions you have to 'escape' it.</blockquote>

[QUOTE="RoChess, post: 1092311, member: 18896"] RegExp is actually pretty easy once you break it up into small groups. Expresso is an awesome builder/tester of expressions, and it also auto-breaks the long expressions up. (...) capture group (?<name>....) named capture group (?:....) capture group, but excluded from results As to the one for you: |\s*\[[A-Z\s,]+\] | = like an 'or', so A|B means look for A or B, so it can be added to the existing one \s = space, \s* means look for 0+ spaces, if you want to force 1+, then it would be \s+ \[ = the actual '[' char, because [ is used in Regular Expressions you have to 'escape' it. [...]+ = match all the characters within at least 1+, including ranges A-Z = A to Z, \s = space, "," = comma \] the actual ']' char, because ] is used in Regular Expressions you have to 'escape' it. [/QUOTE]

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