home
products
contribute
download
documentation
forum
Home
Forums
New posts
Search forums
What's new
New posts
All posts
Latest activity
Members
Registered members
Current visitors
Donate
Log in
Register
What's new
Search
Search
Search titles only
By:
New posts
Search forums
Search titles only
By:
Menu
Log in
Register
Navigation
Install the app
Install
More options
Contact us
Close Menu
Forums
General Forums
Newcomers Forum
New user moving from Windows Media Centre
Contact us
RSS
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Reply to thread
Message
<blockquote data-quote="Owlsroost" data-source="post: 1143381" data-attributes="member: 83973"><p>As mm has explained, the 'under the hood' logic is simple (assuming all timeshifting is <strong>on the same drive</strong>):</p><p></p><p>Maximum possible total timeshift file usage (per <strong>server</strong>) = available disk space on timeshift drive - one file size.</p><p>Minimum space required per client stream = min timeshift files x file size.</p><p>Maximum space required per client stream = max timeshift files x file size.</p><p></p><p>Timeshifting will not work correctly (for a stream) unless there is always sufficient disk space for (min timeshift files x file size) per stream.</p><p></p><p>There is no 'friendly sharing' between the timeshifting processes - it's a free-for-all competition in terms of getting available disk space.</p><p></p><p>(I'm being careful here referring to 'client streams' because MP2 has Picture-in-Picture support, so could have 2 streams per client).</p></blockquote><p></p>
[QUOTE="Owlsroost, post: 1143381, member: 83973"] As mm has explained, the 'under the hood' logic is simple (assuming all timeshifting is [B]on the same drive[/B]): Maximum possible total timeshift file usage (per [B]server[/B]) = available disk space on timeshift drive - one file size. Minimum space required per client stream = min timeshift files x file size. Maximum space required per client stream = max timeshift files x file size. Timeshifting will not work correctly (for a stream) unless there is always sufficient disk space for (min timeshift files x file size) per stream. There is no 'friendly sharing' between the timeshifting processes - it's a free-for-all competition in terms of getting available disk space. (I'm being careful here referring to 'client streams' because MP2 has Picture-in-Picture support, so could have 2 streams per client). [/QUOTE]
Insert quotes…
Verification
Post reply
Forums
General Forums
Newcomers Forum
New user moving from Windows Media Centre
Contact us
RSS
Top
Bottom