Unable to connect to own computer? (1 Viewer)

[Jedipottsy]

MediaPortal Version: not installed yet
MediaPortal Skin: not installed yet
Windows Version: XP Pro sp2 - fresh install yesterday
CPU Type: core 2 duo E6300
HDD: 160gb WD NTFS
Memory: 2gb DDR2 ram
Motherboard: 775DUAL-VSTA
Motherboard Chipset: VIA
Motherboard Bios: Latest
Video Card: 7900gto
Video Card Driver: 97.41
Sound Card: Audigy 2 zs
Sound Card AC3:
Sound Card Driver: latest driver
1. TV Card: WinTV Nova-t Stick
1. TV Card Type: DVB-T
1. TV Card Driver: 3.3c
2. TV Card:
2. TV Card Type:
2. TV Card Driver:
3. TV Card:
3. TV Card Type:
3. TV Card Driver:
4. TV Card:
4. TV Card Type:
4. TV Card Driver:
MPEG2 Video Codec: K-Lite codec pack
MPEG2 Audio Codec: ""
Satelite/CableTV Provider:
HTPC Case:
Cooling:
Power Supply: 600w enermax
Remote: nop
TV:
TV - HTPC Connection:


installed mysql - everything went fine. Installed TV 0.3 Everything went fine. I typed in my computers hostname (0x80) and the mysql usernam and password. Pressed "Test" - works ok. Click save. Nothing happens

i run Mediaportal TV Server - after about 2 minutes a little warning pops up "Unable to connect to 0X80"

both Mysql and TV Server services are started

checking the log shows this error.log file

10/02/2007 03:47:08 Failed to startup cause of exception
10/02/2007 03:47:08 Exception   :System.Net.Sockets.SocketException: A connection attempt failed because the connected party did not properly respond after a period of time, or established connection failed because connected host has failed to respond

Server stack trace: 
   at System.Net.Sockets.Socket.DoConnect(EndPoint endPointSnapshot, SocketAddress socketAddress)
   at System.Net.Sockets.Socket.Connect(EndPoint remoteEP)
   at System.Runtime.Remoting.Channels.RemoteConnection.CreateNewSocket(EndPoint ipEndPoint)
   at System.Runtime.Remoting.Channels.RemoteConnection.CreateNewSocket()
   at System.Runtime.Remoting.Channels.SocketCache.GetSocket(String machinePortAndSid, Boolean openNew)
   at System.Runtime.Remoting.Channels.Tcp.TcpClientTransportSink.SendRequestWithRetry(IMessage msg, ITransportHeaders requestHeaders, Stream requestStream)
   at System.Runtime.Remoting.Channels.Tcp.TcpClientTransportSink.ProcessMessage(IMessage msg, ITransportHeaders requestHeaders, Stream requestStream, ITransportHeaders& responseHeaders, Stream& responseStream)
   at System.Runtime.Remoting.Channels.BinaryClientFormatterSink.SyncProcessMessage(IMessage msg)

Exception rethrown at [0]: 
   at System.Runtime.Remoting.Proxies.RealProxy.HandleReturnMessage(IMessage reqMsg, IMessage retMsg)
   at System.Runtime.Remoting.Proxies.RealProxy.PrivateInvoke(MessageData& msgData, Int32 type)
   at TvControl.IController.Type(Int32 cardId)
   at SetupTv.SetupTvSettingsForm..ctor()
10/02/2007 03:47:08 Exception   :A connection attempt failed because the connected party did not properly respond after a period of time, or established connection failed because connected host has failed to respond
10/02/2007 03:47:08   site      :Void HandleReturnMessage(System.Runtime.Remoting.Messaging.IMessage, System.Runtime.Remoting.Messaging.IMessage)
10/02/2007 03:47:08   source    :mscorlib
10/02/2007 03:47:08   stacktrace:
Server stack trace: 
   at System.Net.Sockets.Socket.DoConnect(EndPoint endPointSnapshot, SocketAddress socketAddress)
   at System.Net.Sockets.Socket.Connect(EndPoint remoteEP)
   at System.Runtime.Remoting.Channels.RemoteConnection.CreateNewSocket(EndPoint ipEndPoint)
   at System.Runtime.Remoting.Channels.RemoteConnection.CreateNewSocket()
   at System.Runtime.Remoting.Channels.SocketCache.GetSocket(String machinePortAndSid, Boolean openNew)
   at System.Runtime.Remoting.Channels.Tcp.TcpClientTransportSink.SendRequestWithRetry(IMessage msg, ITransportHeaders requestHeaders, Stream requestStream)
   at System.Runtime.Remoting.Channels.Tcp.TcpClientTransportSink.ProcessMessage(IMessage msg, ITransportHeaders requestHeaders, Stream requestStream, ITransportHeaders& responseHeaders, Stream& responseStream)
   at System.Runtime.Remoting.Channels.BinaryClientFormatterSink.SyncProcessMessage(IMessage msg)

Exception rethrown at [0]: 
   at System.Runtime.Remoting.Proxies.RealProxy.HandleReturnMessage(IMessage reqMsg, IMessage retMsg)
   at System.Runtime.Remoting.Proxies.RealProxy.PrivateInvoke(MessageData& msgData, Int32 type)
   at TvControl.IController.Type(Int32 cardId)
   at SetupTv.SetupTvSettingsForm..ctor()

 

[Frodo]

a hostname of 0x80 doesnt sounds good to me;-)

 

[Jedipottsy]

a hostname of 0x80 doesnt sounds good to me;-)

i have lots of computers, and i couldnt think of a good name, so each one is in the format 0x8*. This is to do with hard drives, with 0x80 being the primary, 0x81 being the secondary and so on and so forth. It doesnt sound good, but it helps me remember each computer.

 

[Spooky]

Same thing happens to me now all of a sudden. It worked an hour ago, before I installed a different DVB-S card. I already checked simple things like Firewall or even the Antivirus blocking the local connection, but no luck so far (and nothing changed with the rest of the software in the last hour) :|

 

[Paranoid Delusion]

Sounds like the database is locked onto the original cards .

Chances are you maybe able to delete card references in each db location or just drop the database altogether, use latest svn, has a import utility, so all recorded TV will come back as required.

 

[Spooky]

Ah I see. Well at the current state it's probably easier to uninstall everything again, wipe the DB completely and make a fresh install . I don't necessarely need anything ported over from the old installation.

However, how do I reset the database completely? (MSSQL in my case, as already mentioned.)

 

[Paranoid Delusion]

Just drop the database using sql manager (you did install it, if not do it now).

you will have to stop the tvservice for this.

Sorry deleted other post, do not like double posting on same subject.

Cheers

 

[Spooky]

Thank you very much, everything seems to work again

Yeah I am sorry about that thread. I was a little bit hasty and found this thread later on.

 

[Paranoid Delusion]

Something like this instead of latching to an old thread (more than 3 months) you are better off just creating a new one, after a search of course could be something recent that may affect a few people and may just have the answer already there.